5.00 mL of 0.250 M HClO4 diluted to 30.0 mL
2007-11-02 11:19:10 · 3 answers · asked by JTOWN 2 in Science & Mathematics ➔ Chemistry
i don't know anything about chem, but here's a pH calculator
http://www.sensorex.com/support/education/pH_calculator.html
2007-11-02 11:26:11 · answer #1 · answered by 1080 6 · 0⤊ 0⤋
First calculate the final molarity of the strong acid. You can use M1V1=M2V2 to do that.
The concentration of hydronium ions will be equal to that molarity because the acid is a strong acid. Knowing that just calculate the -log[H+] and you've got it.
You should get something like 1.38 for your final answer.
2007-11-02 11:31:30 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋
5mL=0.005L
30mL=0.03L
0.25mol/L*0.005L=0.00125mol [Amount of H+in the solution, i.e. 5mL and therefore the dilution]
0.00125mol/0.03L=0.0417mol/L
pH=-lg c(H+)
pH=-lg0.0417=1.38
2007-11-02 11:35:34 · answer #3 · answered by klimbim 4 · 1⤊ 0⤋