Molarity Problem?

Question

Glycerol, C3H8O3, is a substance used extensively in the manufacture of cosmetics, foodstuffs, antifreeze, and plastics. Glycerol is a water-soluble liquid with a density of 1.2656 g/mL at 15°C. Calculate the molarity of a solution of glycerol made by dissolving 80.000 mL glycerol at 15°C in enough water to make 300.00 mL of solution.

Answer 1

try converting ml to mass then determine the number of moles from that. Since Molarity is moles/liter you can figure it out from there.
PhD Food Chemistry and Nutrition

Answer 2

Atomic weights: C=12 H=1 O=16 C3H8O3=92

Let glycerol be called G. Let the solution be called S

80.000mLG/300.00mLS x 1.2656gG/1mLG x 1molG/92gG x1000mLS/1LS = 3.6684 moles G per L solution, which is molarity.