After sitting at rest for a moment, the bee runs toward the other end with a velocity 1.49 cm/s relative to the still water. What is the speed of the 4.85 g stick relative to the water? (Assume the bee's motion is in the negative direction.)
2007-11-02 10:25:14 · 2 answers · asked by scoota 1 in Science & Mathematics ➔ Physics
since there is no mention of the viscosity of the water I assume is considered frictionless...?
In that case by conservation of momentum the momentum of the bee = momentum of the stick.
momentum is mass x velocity.
the bees velocity on the stick is the sum of his motion relative to the water, and the motion of the stick relative to the water. so
mass of stick x speed of stick = mass of bee x (1.49 - speed of stick)
4.85 x V = 0.175 x (1.49 - V)
Can you solve for V from there?
2007-11-02 11:40:09 · answer #1 · answered by Piglet O 6 · 0⤊ 0⤋
PG-13
2016-04-02 01:10:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋