sodium ( Na) is an group i of the periodic table fluorine (f) in group Vll.?

Question

how can i show what happens to the electrons when NaF is formed by ionic bonding

Answer 1

this is the most impossible question to ask without a drawing pad. but ill try and discribe it. i hope you know what 'dot and cross' diagrams are
sodium has 1 electron in its outer shell and flourine needs 1. so draw the 1 outer electron in the ring of the sodium overlapping into the empty spot where that be that 8th electron of the flourine

Answer 2

The one valence electron that Na has will be attracted to F, This gain of an electron will give F an overall charge of -1 charge due to the imbalance of electrons and protons. The Na on the other hand will lose the electron resulting in a +1 charge, one more proton than electron. Opposites attract and together, they will form Sodium Fluoride

Answer 3

Na, will give it's valence electron to Flourine. The both will become stable, or 'happy' when Na - (looses an electron & F gains an electron)

You could just simply draw a lewis structure, and using arrows show how the sodium atom donates it's electron to flourine.

Answer 4

[Na]^+ [F]^-
2.8 2.8

NB Within the limits of my answer I cannot show the electron structure. However, to diagrammatically show ionic bonding, draw to sets of square brackets. Inside the first pair write Na and put 3 concentric circles around the Na. On the inner most circle put two electrons, on the middle circle 8 electrons.On the outer circle leave 'electron' blank.To the top right (superscript) write a 'plus'(+) sign, and underneath, write '2,8' to indicate the electron structure of the Na ion.
Inside the second pair write F and put 2 concentric circles around the F. On the inner most circle put two electrons, on the outer circle 8 electrons, 7for F and 1 gained ionic ally.To the top right (superscript) write a 'minus'(-) sign, and underneath, write '2,8' to indicate the electron structure of the F ion.

Answer 5

The Na loses its single valence electron to the Fluorine outer shell ('L') to give it a full shell of 8 electrons.
The Na becomes Na+ and the 'F' becomes 'F-', giving the Ionic bonding of the two.
The 'F-' ion electron configuration takes on that of the Noble Gas...Neon. ('F', of course, doesn't become Neon).

Answer 6

try drawing bohr rutherford diagrams or show the bondings