2007-11-02 06:52:25 · 4 answers · asked by smileyD 1 in Science & Mathematics ➔ Mathematics
Factor both numerator and denominator:
{a(a+4)} / {(a-1)(a+4)}
Now, cancel the (a+4) from each, and you end with:
a/(a-1)
that's it!
2007-11-02 06:58:09 · answer #1 · answered by Marley K 7 · 0⤊ 0⤋
To simplify, you should factor.
a^2+4a/a^2+3a-4
a(a+4)/(a+4)(a-1)
There is a term of a+4 both in the numerator and denominator. This allows us to cancel them out.
We will now gte an answer of:
a/a-1
2007-11-02 13:58:28 · answer #2 · answered by aba 2 · 0⤊ 0⤋
a^2+4a/ a^2+3a-4
a(a+4)/ (a+4)(a-1)
a+4 's cancel out
answer a/ a-1
2007-11-02 14:14:00 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
a^2+4a --> a(a+4)
a^2+3a-4 --> (a+4)(a-1)
Canceling the common (a+4) leaves:
a/(a-1).
2007-11-02 13:58:20 · answer #4 · answered by Scott 3 · 0⤊ 0⤋