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F is a function with exponential decay. Explain why function G defined by g(x) = 1/F(x) is a function with exponential growth?

2007-11-02 06:20:57 · 2 answers · asked by ngathile 2 in Science & Mathematics Mathematics

2 answers

F = Ce^-x which gives decay because of negative exponent.
G = 1/F = 1/Ce^-x = e^x/C = growth because + exponent

2007-11-02 06:30:28 · answer #1 · answered by ironduke8159 7 · 0 0

F(x) = Ae^(-kx) ... where k is positive...

G(x) = 1/[Ae^(-kx)] = 1/A e^kx

thus G is an exponential growth function...


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2007-11-02 06:26:33 · answer #2 · answered by Alam Ko Iyan 7 · 0 0

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