No, the velocity gradient is the partial derivative (derivative for a fixed point in time) of velocity with reference to *position* within a continuous medium (usually a fluid). This is easiest to understand in one dimension, where it's just dv/dx. This would be positive, for example, for a river whose current speed increased as you travel downstream in the x-direction. In general though, both velocity and position are vectors, so the gradient has 9 components (1 for each permutation of velocity and position component). This is usually represented by a 3 by 3 matrix called a tensor. For example, one component is dv_x/dy where v_x is the component velocity in the x direction. It would be a measure of flow shear, or how much it changes as you move in the y direction (towards the shore, say, in the above example).
2007-11-02 06:02:19
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answer #1
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answered by Dr. R 7
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Velocity Gradient Definition
2016-12-10 15:02:00
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answer #2
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answered by getts 3
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Question Fluid Mechanics: How to find the velocity gradient? Hi, guys, I've been thinking this over and over but I still can't seem to get it! Please help. Question: Calculate the velocity gradients for y=0, 0.2, 0.4 and 0.6 m if the velocity profile is a quarter circle having its center at 0.6m from the boundary. Answers: infinity/s, 14.9/s, 5.9/s, 0/s I've tried solving it but I do not know where I'm going wrong. I must be stumbling when I'm replacing the circle formula.. Help please? The big question is.. what is the process? Your Answer: What's your source? Share the sites you referenced in your research and give credit. Preview Tip: Be as specific and detailed as you can. Use any personal experience or knowledge you might have. You can use research to help support your answer. Close Tip Search Do a little research: This is a great way to add support to your
2016-03-17 01:32:14
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answer #3
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answered by Anonymous
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For the best answers, search on this site https://shorturl.im/axVDm
The velocity gradient is dv/dy right? So...you just have to find the slope of the velocity curve with respect to y. a quarter circle's equation is: r = sqrt(y^2 + v^2) where y is y and v is velocity and r is a constant (.6) So, find the slope of this equation by differentiating it and solving for all the values of y that you need.
2016-04-05 06:00:47
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answer #4
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answered by Anonymous
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RE:
what is velocity gradient?
2015-08-16 20:35:35
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answer #5
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answered by Anonymous
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the gradient of derivative of velocity gives the acceleration with respect to time. the integral or area gives the displacement
2007-11-02 05:46:08
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answer #6
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answered by suey 2
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Change in velocity... probably with respect to time.
2007-11-02 05:42:11
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answer #7
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answered by Fred Gauss 2
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