calculate the mass in grams of exactly 6.022 x 10^23 silver atom?

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calculate the mass in grams of exactly 6.022 x 10^23 silver atom?

please help me and show work

2007-11-02 05:35:32 · 3 answers · asked by swole 1 in Science & Mathematics ➔ Chemistry

3 answers

108g

2007-11-02 05:45:28 · answer #1 · answered by think_it_over 2 · 0⤊ 0⤋

6.022 x 10^23 is Avogadro's Number. So, you are talking of one mole of silver. The atomic weight of silver is 107.868, so you are talking about 107.868 grams of silver.

2007-11-02 12:44:03 · answer #2 · answered by mikeb72654 2 · 1⤊ 0⤋

First, convert the number of atoms into moles of atoms by dividing by avogadro's number. Then, multiply the result by the molar mass of Ag.

2007-11-02 12:40:59 · answer #3 · answered by hcbiochem 7 · 0⤊ 0⤋