2007-11-02 05:16:34 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
[03]
2x^2-6x-4=0
Comparing the above expression with standard quadratic equation ax^2+bx+c=0.we get a=2,b=-6 and c= -4
x={6+-sqrt(36+32)/4
=(6+-sqrt68)/4
=(6+-2sqrt17)/4
=(3+-sqrt17)/2
2007-11-02 05:30:35 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
2x^2-6x-4=0
2(x^2-3x-2)=0
x^2-3x-2=0
using the quadratic formula you have D=9-4*1*(-2)=9+8=17
so x= (3屉17)/2
x=(3+â17)/2= 3.56
x=(3-â17)/2= - 0.562
2007-11-02 05:32:20 · answer #2 · answered by Orfeas 3 · 0⤊ 0⤋
divide through by 2 to get x^2-3x-2
not factorable
use quadratic formula to get x = [3 +/- (root 17)]/2
2007-11-02 05:26:55 · answer #3 · answered by minorchord2000 6 · 0⤊ 0⤋
x ² - 3 x - 2 = 0
x = [ 3 ± â17 ] / 2
x = 3.56 , x = - 0.562
2007-11-02 05:22:08 · answer #4 · answered by Como 7 · 0⤊ 1⤋
Delta= (-6)^2 -4*2*(-4) = 68
X1,X2 =[-(-6)(+,-)( Delta)^(.5)]/(2*(-6))
2007-11-02 05:24:23 · answer #5 · answered by Freddie 2 · 0⤊ 0⤋
Use the quadratic formula.
2007-11-02 05:21:50 · answer #6 · answered by DWRead 7 · 0⤊ 0⤋