Calculate the work done when 50.0 g or tin dissolves in excess acid at 1.0 atm and 25 degrees Celsius?

Question

Sn(s) + 2H+(aq)-------yields---Sn 2+(aq) +H2(g
Assume ideal gas behavior

Answer 1

Sn(s) + 2H+(aq) ==> Sn(2+)(aq) +H2(g)
The work is done by releasing H2 gas.
The molar mass of Sn: 118.71 g/mol.
50.0g Sn <=> 0.421 mol Sn ==> reacted to get 0.421 mol H2
==> W = nRT = 0.421*8.314*298 = 1.04 kJ
while the given pressure 1.0 atm is not necessary.