Ordered pairs?

Question

What would be 3 ordered pairs for the following equation?

y= -3^(x+2) -4

Answer 1

Just pick some values for x, and then calculate y.

For example, try x = 0:
y = -3^(0+2) - 4
y = -(3²) - 4
y = -9 - 4
y = -13
(0, -13)

Or x = 1:
y = -3^(1+2) - 4
y = -(3^3) - 4
y = -27 - 4
y = -31
(1, -31)

Let's try x = -1:
y = -(3^(-1 + 2)) - 4
y = -(3^1) - 4
y = -3 - 4
y = -7
(-1, -7)

Or x = -2:
y = -(3^(-2 + 2)) - 4
y = -(3^0) - 4
y = -1 - 4
y = -5
(-2, -5)

There are 4 ordered pairs for you. The hardest part of this is to remember in formal mathematics the exponent takes precedence over the negative sign. So do that first, then handle the negative sign.

Answer 2

To find any ordered pairs, choose a value for x, plug it in and find the corresponding value of y.

x = 0 gives y = -3^(0+ 2) -4 = -13
(0, 13)

Other pairs would be:

(1, -31)
(2, -85)
(-1, -7)

Answer 3

1) ordered pairs are in the form of (x,y)

2) All you have to do is to pick any number for x and put it into your equation for x and solve for y.

.

Answer 4

Let (x,y) be the ordered pair then
1.(1,-31)
2.(2,-85)
3.(3,-247)

Best wishes!