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they both get mean when it comes down to it

2007-11-02 02:07:31 · 20 answers · asked by Anonymous in Entertainment & Music Polls & Surveys

20 answers

a rock? or did you mean a rott? i really haven't heard of the "rock" dog.

2007-11-02 02:10:19 · answer #1 · answered by Anonymous · 1 0

I guess it would depend on what type of "rock" it is. Are we talking about a grain of sand or a boulder? If it is bigger than a softball I would say the rock. But smaller and I don't think the pit would notice.

2007-11-02 09:13:43 · answer #2 · answered by michaelrayburn 2 · 0 0

first of all its a Rottweiler not rockweiler 2nd dog fights are stupid and pits are naturally nice dogs as are most dogs when getting treated like a living animal

2007-11-02 09:11:47 · answer #3 · answered by *I Need More Cowbell* 5 · 2 0

A pitbull would win over the ROTTweiler (not rockweiler). A pitbull has a jaw strength of 3000 lbs and can deglove a person. Their jaws are much stronger. They're also faster and more agile.

2007-11-02 09:15:21 · answer #4 · answered by Mickey Mouse Spears 7 · 0 1

you sadist!!!! but i have seen this(which it's sickening) and I am not the one to judge your tastes, but a rottweiler is slow and sluggish and has little coordination and balance. the only good they got is the brute force they have. so if the pit is quick on it's toes, it can take down the rott. the moment the pit is distracted, it's goodnnite sleep tight for the pit.

2007-11-02 09:12:07 · answer #5 · answered by Anonymous · 0 2

A pit

2007-11-02 09:14:52 · answer #6 · answered by Murders Princess 5 · 0 2

A rock since you could use it to smash the pit bull's head.

2007-11-02 09:14:09 · answer #7 · answered by Anonymous · 0 2

im thinking the pit

2007-11-02 09:10:36 · answer #8 · answered by ? 7 · 0 2

I think you mean a "Rott" not "rock". They're rottweilers not rockweilers. and that is not cool either one you use. It's cruel and illegal.

2007-11-02 09:17:40 · answer #9 · answered by ♦ Phoenix Rising♦ 6 · 0 0

pit

2007-11-02 09:12:53 · answer #10 · answered by Anonymous · 0 1

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