A 2.04 L vessel contains 4.68 g of a gas @ 1 atm and 27 degree C. Calc. density in g/L & Molar mass of the gas

Question

need to see how to work it out so I can learn

Answer 1

density easy divide mass by volume 4.68/2.04 =2.294g/L
molar mass pV =nRT
so n number of moles is

n=pV/RT (I use MKS units p =101325 pa , V =2.04*10^-3m^3,
R= 8.31 , T=300(27+273))
So n = 101.325*2.04 *10^-3/8.31*300 =0.083 mole
and 0.083 mole corresponds to 4.68g
so 1mole =4.68/0.083=56.4g

Answer 2

If this is basic, why are you asking us? assume you have a million L of gasoline. Mass of the gasoline is a million.40 9 g Moles = PV/RT = 4.376 * 10^-2 moles Molar mass = a million.40 9 g / 4.376 * 10^-2 moles = 34.a million g/mole