the sum of the digits of a two digit number is 13. when the digits are interchanged, the original number is gr

Question

eater than 27.what is the original number?

Answer 1

Let the digits be x and y.
the number is xy
it is expressed as 10x+y
x+y=13 [given in the question]
x=13-y

when the number is interchanged it becomes=10y+x

EQUATION:
10x+y=[10y+x]+27[given in the question]

when u substitute x=13-y
10[13-y]+y=[10y+13-y]+27
130-10y+y=9y+13+27
130-9y=9y+40
130-40=9y+9y
90=18y
y=90/18
y=5

THEREFORE x=13-5
=8

the original number is xy
therefore the number is 85.

THIS IS THE EXACT ANSWER . BELIEVE ME.
WHEN INTERCHANGED THE NUMBER BECOMES=58.

Answer 2

It's a little unclear from your question what you meant. There are only 3 combinations of digits that can add up to 13:

4 + 9 = 13
5 + 8 = 13
6 + 7 = 13

Forming numbers out of these and subtracting the smaller from the larger the results are:
94 - 49 = 45
85 - 58 = 27
76 - 67 = 9

So if you want the *difference* to be greater than 27, then only the combination of 94 and 49 will work.

Answer 3

I think you're missing some text there. Possible numbers are
94
85
76
67
58
49.
If you compare the original number to the reversed number:
94 - 49 = 45
85 - 58 = 27
76 - 67 = 9
67 - 76 = -9
58 - 85 = -27
49 - 94 = -45
So if you meant that when you reverse the digits, the original number is greater than 27 more than the reversed number, you must have the original number as 94.

Answer 4

It could be any of the below numbers:

49
58
67
76
85
94

Get the pattern?


Good luck.