In a sanctuary there were1600 animals.Their no. increases by 5% every year.What will be the no. of animals after 2 years?
2007-11-01 21:34:23 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
After one year, increase by 5% of 1600 = 5/100 × 1600 = 80. So total after 1 year is 1680.
The increase in the second year is 5% of 1680 = 5/100 × 1680 = 84. So the total after the second year is 1680 + 84 = 1764.
An alternate method is to say that increasing by 5% corresponds to multiplying by (1 + 5/100) = 1.05. Then increasing by 5% a year for two years corresponds to multiplying by (1.05)^2. So the total after two years is 1600 × (1.05)^2 = 1764.
2007-11-01 21:41:41 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
The first year:
1600 + (1600 * 5/100) = 1600 + 80 = 1680
Second year:
1680 + (1680 * 5/100) = 1680 + 84 = 1764
Good luck.
2007-11-02 04:45:54 · answer #2 · answered by ¼ + ½ = ¾ 3 · 0⤊ 0⤋
This is just a compounding problem.
N = N0 ( 1 + i) ^ n
This is the same formula for appreciation of goods or compound interest in finance.
And with a minus sign instead of the +, for depreciation.
N0 = 1600
i = 5% = 0.05
n=2
N = 1600 * ( 1+0.05)^ 2
N = 1764
2007-11-02 04:45:23 · answer #3 · answered by Anonymous · 0⤊ 0⤋
As already answered 1,764 is the correct answer!
My Explenation: 40 x 40 = 1,600. After 1st year 1,680.
Then ADD 5% AGAIN 40 x 105% = 42. 42 x 42 = 1,764!
Additional Trivia: 40 x 40 = 1,600 & 42 x 42 = 1,764.
5% of 40 is 42. Math_Maestro!
2007-11-02 04:49:21 · answer #4 · answered by Math_Maestro 7 · 0⤊ 0⤋
After year 1
1600 + 80 = 1680
After year 2
1680 + 84 = 1764
2007-11-02 06:18:38 · answer #5 · answered by Como 7 · 0⤊ 1⤋
General Equation:
1600 x (1.05)ⁿ
where n is the number of years
If n = 2,
1600 x (1.05)²
= 1764
2007-11-02 05:13:01 · answer #6 · answered by ideaquest 7 · 0⤊ 0⤋