Find initial velocity and time of rocket.?

Question

Find the initial velocity of the rocket shooting up at 150 feet. (Assuming it went up straight) Find the time it takes to go up.

THis is my last problem and i am stuck please help!

Answer 1

v^2 = 2 gh = 2 x 32 x 150
v = 97.98 m/s

Time t = v / g = 97.98 / 32 = 3.06 s

Answer 2

kuiper & akm each received it proper, however needed to anticipate that the rocket had all its preliminary pace at 0 peak. As all recognize who've visible house trip launches, the ballistic flight course does not start till the entire rocket thrust ceases........

Answer 3

2,334,453 feet a sec

now divide by 150

Answer 4

Given:
dy =150 feet

Find:
vi = ?
t = ?

Solution:

FIRST, convert..
150 ft (0.3048m/1ft) = 45.72 m

SECOND, find time...
t = sqrt 2dy/g
t = sqrt 2(45.72m)/(9.8m/s^2)
t = sqrt. 9.330612245 s^2
t = 3.054605088 s

THIRD, find vi...
vf^2 = vi^2 + 2gd
0 = vi^2 + 2gd
-vi^2 = 2(9.8m/s^2)(45.72m)
-vi^2 = 896.112m^2/s^2
sqrt.[-vi^2 = 896.112m^2/s^2]
-vi = 29.93512986 m/s
-(-vi = 29.93512986 m/s)
vi = - 29.93512986 m/s
vi = -30 m/s

Good luck and God bless!

Answer 5

v0^2 = 2gh = 2*32.2*150 = 9,660 ft^2/s^2
v0 = 98.28530 fps
t = v0/a = 98.28530/32.2 = 3.0523 s