math help!?

Question

2
(x1-1)( x + 3x + 2)

(one x take away one)(x to the second power plus three x plus 2)


he wants us to multiply

Answer 1

(x - 1) (x² + 3x + 2)
x³ + 3x² + 2x - x² - 3x - 2
x³ + 2x² - x - 2

Answer 2

(x-1)(x^2 +3x +2)

Multiply the x in the first parentheses times everything in the second parentheses, and then multiply -1 times everything in the second parentheses. Combine like terms.

x^3 +3x^2 +2x -x^2 -3x -2

= x^3 +2x^2 -x -2

By the way, putting this symbol ^ means to a power. So x^2 is x squared. It's easier to type it that way for me.

Answer 3

(x - 1)( x^2 + 3x + 2)

Okay, so you have to distribute the first part of the problem; (x-1), into the second ( x^2 + 3x +2)
So take the x in the first parenthesis and multiply it by each term in the second parenthesis.
x^3 +3x^2 + 2x
Now take the -1 and again distribute it through the second parenthesis.
-x^2-3x-2
Finally combine alike terms and you have your answer.
x^3+2x^2-x-2

Answer 4

You want
(x-1)( x^2 + 3x + 2)?

Step 1: forget that foil stupidity, ok?

Step 2: learn to DISTRIBUTE:

x*( x^2 + 3x + 2) - 1*( x^2 + 3x + 2), see how you break it apart? Expand

x^3 + 3x^2 + 2x - x^2 - 3x - 2, see how you distribute? gather

x^3 + 2x^2 - x - 2, done.

Answer 5

x^2 readed as x to the second power.

(x-1)(x^2 + 3x +2)

to be easy to understand it, we multiply it by distributing x-1 to the second part of equation.

x^2 *(x-1) + 3x *(x-1) + 2 *(x-1)
x^3 - x^2 + 3x^2 - 3x + 2x -2

adding the similar terms, and the answer is

x^3 + 2x^2 - x - 2 ...............(final answer)

Answer 6

(x-1)(x²+3x+2)
=x³+3x²+2x-x²-3x-2
=x³+2x²-x-2

Answer 7

x³+2x²-x-2