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Just for fun, I was doing a proof of propositional logic, but I got stuck trying to prove that Pv(QvR) implies (P&Q) v (P&R).

I tried assuming the negation of (P&Q) v (P&R) --in order to negate that later and get (P&Q) v (P&R)-- but it's not getting me anywhere... anyone know the answer?

2007-11-01 19:16:17 · 2 answers · asked by Flaze 3 in Science & Mathematics Mathematics

2 answers

It isn't a true statement.
Suppose Q is the only true statement.
Then the antecedent is True and the consequent is false. This makes the implication false.

2007-11-01 19:24:09 · answer #1 · answered by Demiurge42 7 · 0 1

Pv(QvR) is not logically equivalent to (P&Q) v (P&R).

P&(QvR) is logically equivalent to (P&Q) v (P&R) through distribution.

2007-11-02 09:21:32 · answer #2 · answered by mitten 5 · 0 0

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