The forces acting on a 2.8kg mass are F1=F1xi-F1yj and F2=F2xi+F2yj where F1x=3N, F1y=8N, and F2x=6N, and F2y=2N and I have to find the magnitude a of the acceleration of the particle. We were told to use a=F1x+F2x/m i + -F1y+F2y/m j, then a=axi+ayj so what I did was 3+6/2.8 + -8+2/2.8 but I got the answer wrong if you know could you help me out please.
There was an example and it was that a 2kg mass is acted on by four forces F1 is 10 N due E, F2 is 8 N due N, F3 is 16 N due S, and F4 is 1 N due W. And the answer for the magnitude of the acceleration was 6.02 but I don't get how they got it so I don't get the other question.
2007-11-01 17:35:17 · 1 answers · asked by glance 3 in Science & Mathematics ➔ Physics
Net Fx=9 and Fy=-6
a=F1x+F2x/m i + -F1y+F2y/m j should be
a=[F1x+F2x] / m i + [-F1y+F2y] / m j
=9/2.8 i - 6/2.8 j
and magnitude is = [(81+36)^.5] / 2.8
2007-11-01 18:20:49 · answer #1 · answered by meg 7 · 0⤊ 0⤋