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if f(x)= e^2x - 5e^x + 6=0 has 2 solutions,
what is the smaller solution?
what is the larger solution?

2007-11-01 17:32:08 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

Let y = e^x
y² - 5y + 6 = 0
(y - 3)(y - 2) = 0
y = 3 , y = 2
e^x = 3 , e^x =2
x = ln 3 , x = ln 2
x= ln 3 is the larger solution.

2007-11-02 04:09:36 · answer #1 · answered by Como 7 · 0 1

Do a substitution: u=e^x.

Then your equation becomes u^2 - 5u + 6 = 0.

Solve for u; you get -1 and 6.

So -1 = e^x and 6 = e^x, replacing the values in the substitution.

e^x cannot equal -1, so that can't be a solution.

For the other one, take the ln of both sides and you get x = ln(6).

2007-11-01 17:43:37 · answer #2 · answered by maedko 2 · 0 1

factor it ...e^x=3, or e^x=2 etc
x=ln3 or x=ln2
[(e^x-3)(e^x-2)=0 is e^2x-5e^x+6=0]

2007-11-01 17:46:02 · answer #3 · answered by azteccameron1 4 · 0 0

Como's solution is correct

2007-11-02 06:36:54 · answer #4 · answered by Red Campion 2 · 0 0

use the discriminant

2007-11-01 20:37:21 · answer #5 · answered by stuartelliott797 2 · 0 0

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