calorimeter question, Urgent!!?

Question

I need help with my calculation. I'm not so sure whether i'm doing this correctly or not.
Well...i start with
SW△T(unknown metal)= SW△T(H2O) + C△T(calorimeter)
I need to find the specific heat of the unknown metal.
data I've collected from the exp are as follows:
△T of H2O in calorimeter
mass of unknown metal
mass of water used
boiling water temperature
Now..my question is where do i use the temperature of the boiling water??
For C△T, I've specific heat of calorimeter *△T in calorimeter
For SW△T(H2O), specific heat of H2O*mass of H2O used*△T(but I don't whether I should use △T of H2O in cal or boiling temperature of H2O)
Finally, SW△T(metal), mass of metal*△T(I was thinking of using △T of H2O in calorimeter since temp of H2O=temp of metal) So, please let me know which one I should use and if what I've come up with is correct. And, no disrespectful answers. Thank you!!!

Answer 1

I believe that you neglected some key factors. May I guess:
Did you put the unknown metal into the water and boil them together?
Did you immediately transfer the metal from the boiling water into the calorimeter?
Did you wait till the temperature stabilize inside the calorimeter?
Do I read the little square  and T as Delta T?
If your answers to all my questions are "Yes", then I can help you.
The Delta T in "SW△T(unknown metal)" is (100C - (final T in calorimeter)). This term calculate the heat provided by dropping the temperature (from 100C) of the unknown metal.
The Delta T in "SW△T(H2O)" is ((final T in calorimeter) - initial T in calorimeter). This term calculate the heat absorbed by water in calorimeter.
The Delta T in "C△T(calorimeter)" is ((final T in calorimeter) - initial T in calorimeter). This term calculate the heat absorbed by calorimeter itself.
The equation is a heat balence equation: the heat released must be the heat absorbed, and the final temperature must be the same.
On your question whether you should use "△T" of H2O in cal, I believe that you have mistaken "specific heat" to "△T". Now, the unit must be consistant. If you used Cal or J in all the other specific heat and heat capacity, you have to use the same for water. OK?