Math word problem?

Question

The perimeter of the square is equal to the perimeter of the triangle. The sides of the triangle are equal in lenght. ( The square has sides 2x+3 and 3x, the triangle has side 5x-3)

a. without doing any calculations estimate which figure has the greater side lenght. Explain your choice.

b.What is the side lenght for each figure?

c. What is the perimeter of each figure?

This problem is drivin me crazy and I don't know how to do it.

Answer 1

a. The triangle has the greater side length.

Explanation.

Given:

1) The perimeter of the triangle is equal to the perimeter of the square.

2) All sides of the triangle are the same. 3 sides

3) All sides of a square are equal. 4 sides.

Logically, the sides of the triangle must be greater since it only takes three of them to equal all four of the square.

Another way to think about this is as follows:

I have $100 in each hand. In my right hand, I have 5 bills. In my left hand I have 2 bills. Which hand has the larger bills?


b. The square has sides of 9 units and the triangle has sides of 12 units.

Given:
1) the square has sides of 2x + 3, and 3x.
2) the triangle has sides of 5x - 3.

For the square.
Since ALL sides of a "square" are the same..
2x + 3 = 3x, solve for x.
.........3 = x

viola! x = 3

3x, and 2x +3

3•3=9, and 2•3 + 3 = 9

Square has sides of 9 units.

For the triangle...

it has sides of 5x - 3. Since x = 3, (5•3) - 3 equals 15 - 3, which equals 12.


c. Square has perimeter of 4 • 9 which equals 36 units. And triangle has perimeter of 3 • 12 which equals 36.

Answer 2

The triangle has greater side length. Here's how you know without calculations: The perimeters are the same, and the triangle has 3 equal sides. The square will have 4 equal sides. The square's sides must be smaller (because there are 4 of them) to equal the same perimeter as the 3 sided triangle. 4 little square sides to equal 3 larger triangle sides.
b. Square sides are 9, triangle sides are 12. How? Equate the square sides to the triangle sides....(2x+3) + (2x+3) + 3x+3x=(5x-3) +(5x-3)+(5x-3)
You will find that x=3, and then put that x value back into the sides calculations.
c. square is 36, triangle is 36. Just put the x value into the calculation for perimeter of a square and perimeter of the triangle.

Answer 3

a) Since the perimeters are equal, the sides on the triangle must be longer because it only has 3 sides, while the square has 4 sides.

b) To answer this you don't even need to know the side length of the triangle. Since all squares have 4 sides of the same length, we know that 2x+3 = 3x. Subtract 2x from both sides and you get x=3. For the square, 3x=9 (or 2x+3=9). For the triangle, 5x-3=12. (If you didn't have the 3x for the other side of the square, you would say 4(2x+3)=3(5x-3), since we know both perimeters are equal, and solving for x would also get you to x=3.)

c) For the square, multiply the side length of 9 by 4 to get 36. For the triangle, since we know that all 3 sides are equal, multiply 12 by 3 to get 36.

Answer 4

1. Without calculations, 5x-3 looks bigger than 2x+3. This is because multiplying usually will give a greater result than adding/subtracting.

2. Remember, the o perimeters are equal. The perimiter of a square is 4*L, and since you know all the sides of the tirangle are the same, the perimiter is 3*L.

so, 4(2x+3)= 3(5x-3)
8x + 12 = 15 x - 9
-7x = -21
x = 7

So the length for the triangle = 5(7) - 3 = 32 and the length for the square is 2(7) + 3 = 17.

3. Use the side length to find the perimeter. For the tirangle this is 3*32 = 96 and the square is 4* 17 = 68.

Answer 5

I know the answer for a. would be the triangle, since it has 3 equal sides that equal the same thing as the four equal sides of the square.

as for the rest sorry.

it dosent really make sense though. a square has four equal sides (that is what makes it a square and not a rectangle). now you problem states that the sides of the square are of different lengths 2x+3 and 3x.

Answer 6

Are you sure that the problem says 'square' and not 'rectangle'? All the side lengths of a square are equal, and your problem says that the square has sides 2x+3 and 3x.

Answer 7

30 = -16t^2 + 32t + 50 -16t^2 + 32t + 20 = 0 divide via 4 -4t^2 + 8t + 5 = 0 t = ((-8 +/- sqrt(sixty 4-4(-4)(5))/-8 t = ((-8 +/- sqrt(a hundred and forty four))/-8 = (-8 +/- 12)/-8 t = -20/-8 = 2.5 seconds the different answer, t = -a million/2 2d, represents the theoretical time while the object could have been at 30 ft on the way up. At t = 2.5 seconds, the object is on its way down. It reaches its optimal height at t = a million 2d, while it reached sixty six ft.

Answer 8

it cant be a square !
if has side(S)

it should have one side