2007-11-01 16:46:57 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Figure the prime factors, then you can used that to figure out the lowest common lowest common (LCM) of all the numbers.
2 = 2
3 = 3
4 = 2 x 2
5 = 5
6 = 2 x 3
7 = 7
8 = 2 x 2 x 2
9 = 3 x 3
10 = 2 x 5
So we need 2 x 2 x 2 x 3 x 3 x 5 x 7 in order to cover all the factors.
This is 2520
2520 = 10 x 252
2520 = 9 x 280
2520 = 8 x 315
2520 = 7 x 360
2520 = 6 x 420
2520 = 5 x 504
2520 = 4 x 630
2520 = 3 x 840
2520 = 2 x 1260
2007-11-01 16:50:36 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
Suppose X is the number we consider each digit from 2 thru 10:
X is equally divisible by 2 then X = 2*k
X is equally divisible by 3 then X = 2*3*k
X is equally divisible by 4 then X = 2*3*2*k
X is equally divisible by 5 then X = 2*3*2*5*k
X is equally divisible by 6 already
X is equally divisible by 7 then X = 2*3*2*5*7*k
X is equally divisible by 8 then X = 2*3*2*5*7*2*k
X is equally divisible by 9 then X = 2*3*2*5*7*2*3*k
Because X is smallest so k = 1
X = 2*3*2*5*7*2*3 = 2520
2007-11-01 23:58:13 · answer #2 · answered by Anonymous · 1⤊ 0⤋
I'd go with either that number in the one above me, or 0
2007-11-01 23:55:03 · answer #3 · answered by Brad Y 3 · 0⤊ 0⤋
30,240?
2007-11-01 23:56:14 · answer #4 · answered by gabrielle 1 · 0⤊ 0⤋