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You have a bag of cubical balloons that you inflate at a rate of 40cm^3 per second, how fast will the balloon's surface area get larger when the balloons edges are 4cm long?

I have trouble solving things implicitly so any help on this would be appreciated.

2007-11-01 16:29:33 · 1 answers · asked by John Avry 2 in Science & Mathematics Mathematics

1 answers

Each side of the ballon has an area of x^2 where x is the length of a side. There are 6 sides to a cube. So the total surface area is 6x^2.
A = 6x^2
The volume of the balloon is V = x^3.
You are given dA/dt and want dV/dt.
Solve for x in the volume equation and substitute it in the area equation. Then take the derivative of this with respect to t to get dA/dt in terms of x and dV/dt
It is easy from there

2007-11-01 16:37:49 · answer #1 · answered by Demiurge42 7 · 0 0

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