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From this equation, S(s) + O2(g)--->SO3(g)
Suppose exactly 5g of each reactant is available, determine which reactant is limiting. Showing steps

2007-11-01 15:53:15 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Find out the number of moles of each corresponding to 5g. Then, using the reaction
2S + 3O2 -> 2SO3, figure which, if fully reacted, gives the least yield. Here, the moles are roughly 0.17 each. So, based on all sulfur being consumed, you need 3/2 as much oxygen as you have to form 0.17 moles of product. Based on all oxygen being consumed, you need 2/3(0.17) moles of S to form 2/3 (0.17) moles of product.
So oxygen is limiting.

2007-11-01 16:05:42 · answer #1 · answered by cattbarf 7 · 0 0

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