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This is a particle motion problem. A point moves smoothly along the curve y=x^(3/2) in the first quadrant in such a way that its distance from the origin increases at the constant rate of 11 units per second. Find dx/dt when x=3.
This is a Calculus problem.

2007-11-01 15:41:45 · 8 answers · asked by Anonymous in Education & Reference Homework Help

8 answers

The increment of length along a curve is given by

ds^2 = dx^2 + dy^2

for y = x^(3/2), dy = [(3/2)√x] dx

then ds^2 = dx^2 + (9/4)x dx^2

ds^2 = [1+(9/4)x] dx^2

ds = √[1+(9/4)x] dx; so ds/dx = √[1+(9/4)x]

ds/dt = ds/dx * dx/dt

solve for dx/dt

dx/dt = ds/dt / ds/dx

at x = 3, ds/dx = √[1+27/4] = 2.784; you are given that ds/dt = 11, so

dx/dt = 11/2.783 = 3.95 units/sec

2007-11-01 15:54:24 · answer #1 · answered by gp4rts 7 · 0 0

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2016-11-10 00:23:04 · answer #2 · answered by ? 4 · 0 0

I am not sure, not in Calculus yet. But I'd I would have a better time answering if I knew if you meant probability, or do you really mean possibility!???!!!

2007-11-01 15:45:51 · answer #3 · answered by Amelia:] 5 · 0 0

Ah... I remember why I dropped out of Calculus. Stupid derivatives.

2007-11-01 15:44:59 · answer #4 · answered by Anonymous · 0 0

you need to break it up into parametric equations or use related rates

dy/dx=(dy/dt)/(dx/dt)
dy/dx=(3/2)x^(1/2)
dx/dt=(dy/dt)/(dy/dx)

sorry, i only got it started. hope you can manage the rest

2007-11-01 15:50:17 · answer #5 · answered by Anonymous · 0 0

0 chances from me!I'm in Prep-math.
I can figure out that
1 question= 2 points
thanks

2007-11-01 15:47:48 · answer #6 · answered by noteworthy5 3 · 0 0

You are going to win the "nobody answered this" award...

2007-11-01 15:45:47 · answer #7 · answered by Farmer & Granny Crabtree 5 · 0 1

Can I buy a vowel?

2007-11-01 15:45:24 · answer #8 · answered by Help4me 3 · 0 0

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