The increment of length along a curve is given by
ds^2 = dx^2 + dy^2
for y = x^(3/2), dy = [(3/2)√x] dx
then ds^2 = dx^2 + (9/4)x dx^2
ds^2 = [1+(9/4)x] dx^2
ds = √[1+(9/4)x] dx; so ds/dx = √[1+(9/4)x]
ds/dt = ds/dx * dx/dt
solve for dx/dt
dx/dt = ds/dt / ds/dx
at x = 3, ds/dx = √[1+27/4] = 2.784; you are given that ds/dt = 11, so
dx/dt = 11/2.783 = 3.95 units/sec
2007-11-01 15:54:24
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answer #1
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answered by gp4rts 7
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2016-11-10 00:23:04
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answer #2
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answered by ? 4
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I am not sure, not in Calculus yet. But I'd I would have a better time answering if I knew if you meant probability, or do you really mean possibility!???!!!
2007-11-01 15:45:51
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answer #3
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answered by Amelia:] 5
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Ah... I remember why I dropped out of Calculus. Stupid derivatives.
2007-11-01 15:44:59
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answer #4
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answered by Anonymous
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you need to break it up into parametric equations or use related rates
dy/dx=(dy/dt)/(dx/dt)
dy/dx=(3/2)x^(1/2)
dx/dt=(dy/dt)/(dy/dx)
sorry, i only got it started. hope you can manage the rest
2007-11-01 15:50:17
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answer #5
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answered by Anonymous
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0 chances from me!I'm in Prep-math.
I can figure out that
1 question= 2 points
thanks
2007-11-01 15:47:48
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answer #6
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answered by noteworthy5 3
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You are going to win the "nobody answered this" award...
2007-11-01 15:45:47
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answer #7
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answered by Farmer & Granny Crabtree 5
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Can I buy a vowel?
2007-11-01 15:45:24
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answer #8
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answered by Help4me 3
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