Two Dimensional Collisions?

Question

The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.022 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.062 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with Puck A angle 65 degrees and Puck B 37 degrees.

Find the final speeds of both puck A and puck B?

Answer 1

GIVENS
masses m1, m2 = .022 .062
pre-collision velocities v1i, v2i = 5.5 0
post-collision angles Θ1f, Θ2f = 65 -37 deg
SETUP
P = m1v1i = .121
RESULTS
post-collision velocities v1f, v2f:
v1f = P / ((1/tan(Θ1f) - 1/tan(Θ2f))*m1*sin(Θ1f)) =
3.38392960822387 m/s
v2f = P / ((1/tan(Θ2f) - 1/tan(Θ1f))*m2*sin(Θ2f)) =
1.80827716609214 m/s

Answer 2

Wouldn't the tensile strength of the plastic material used to make these pucks play a role in absorbtion, thus slowing the deflected speed?