Its part of a take home test and i need help!
How do you solve:
5x+2/x^2-4= -5x/2-x + 2/x+2
2007-11-01 14:31:42 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(5x + 2)/(x^2 - 4) = -5x/(2-x) + 2/(x+2)
factorize x^2 - 4 into (x+2) (x-2) and write
-5x(2-x) as 5x/(x-2)
(5x + 2) / (x+2)(x -2) = 5x / (x-2) + 2 / (x+2)
multiply with (x+2)(x-2)
5x + 2 = 5x(x+2) + 2(x-2)
5x + 2 = 5x^2 + 10x + 2x - 4
5x + 2 = 5x^2 + 12x - 4
5x^2 + 7x - 6 = 0
5x^2 + 10x - 3x - 6 = 0
5x(x + 2) - 3(x + 2) = 0
(x + 2) (5x - 3) = 0
x = -2 or 3/5
but x = -2 is not a solution, as denominators x^2 - 4 and x + 2 will be zero when x = -2 and division by zero is undefined
so x = 3/5
2007-11-01 14:55:50 · answer #1 · answered by mohanrao d 7 · 0⤊ 0⤋
5x+2/x^2-4= -5x/2-x + 2/x+2 . . .please write the parenthesis
(5x+2)/(x^2-4)= -5x/(2-x) + 2/(x+2) . . . if this is OK
(5x+2)/(x^2-4)= 5x/(x -2) + 2/(x+2) . . . remove the negative
(5x+2)/(x^2-4)= 5x/(x - 2) + 2/(x+2)
(5x+2) = 5x (x+2 ) +2 (x-2) . common denominator (x²-4)
5x+2 = 5x²+10x + 2 x-4
5x²+ 7x -6 = 0
(5x -3) (x + 2) = 0
x = 3/5 . . . and . . . x = -2
2007-11-01 21:49:23 · answer #2 · answered by CPUcate 6 · 0⤊ 0⤋
5x+2=-5x(x+2)+2(x-2)
5x+2=-5x^2-10x+2x-4
5x+2=-5x^2-8x-4
-5x^2-5x-8x-6=0
-5x^2-13x-6=0
-5x^2-13x-6=0/ -1
5x^2+13x+6=0
(5x+3)(x+2=0
x=3/5;or -2
2007-11-01 21:51:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
5x+2=-5x(x+2)+2(x-2)
5x+2=-5x^2-10x+2x-4
5x+2=-5x^2-8x-4
-5x^2-5x-8x-6=0
-5x^2-13x-6=0
-5x^2-13x-6=0/ -1
5x^2+13x+6=0
(5x+3)(x+2=0
x=-3/5;or -2
2007-11-01 21:46:52 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
that's the problem with take home tests. u can cheat all u want!
i have no idea about the answer, cause i g2g to the bathroom. try math.com.
2007-11-01 21:39:28 · answer #5 · answered by Harris 6 · 0⤊ 0⤋
what exactly do the slash marks mean? division or fraction?
2007-11-01 21:41:34 · answer #6 · answered by Cameron A 1 · 0⤊ 0⤋