Continuity?

Question

F(x)=
square root (-x) x<0
3-x 0<(or equal to)x<3
(x-3)^3 x>3

Where is the function continous?
P.S. Its all part of the function. I don't get this. Please help.

Answer 1

The problematic points are 0 and 3
at 0 lim F(x) x==>0- is 0
lim F(x)x==>0+ =3 so at 0 the F is discontinous
At 3
Lim F(x) x==>3- =0
lim F (x) x==>3+ =0 so at x=3 the function is continuos.
The function is continuos for all real numbers except x=0