Find f(2) given f(x) = 2x^3 - x^2 - 22
[a] 30
[b] -42
[c] - 10
[d] -14
please show me how to do it
thanks :)
2007-11-01 12:59:58 · 5 answers · asked by vennysweetgirl21 3 in Science & Mathematics ➔ Mathematics
hey venny
instead of the x, u put two
u replace the x with the two
therefore u get
2(2)^3 - (2)^2 - 22
16 -4-22
12-22 = -10
answer is c = -10
:)
2007-11-01 14:11:09 · answer #1 · answered by SoCal_Dolphin_Girl 3 · 0⤊ 0⤋
f(x) = 2x^3 - x^2 - 22
For f(2) replace x with 2 wherever x appears. Remember that the * sign is implied whenever there is a coefficient.
f(2) = 2*2^3 - 2^2 - 22
f(2) = 2*8 - 4 - 22
f(2) = 16 - 26
2007-11-01 13:17:27 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
replace 2 in place of x
f(2) = 2(2^3) - (2^2) -22
= 2(8) -4 -22
= 16 -26
= -10. thus answer is c.
cheers.
2007-11-01 13:13:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
f(2) basically means plug 2 into x
therefore
f(2)=2(2)^3-(2)^2-22
f(2)= -10
2007-11-01 13:11:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋
the answer is d. 100%
2007-11-01 13:04:47 · answer #5 · answered by Anonymous · 0⤊ 1⤋