What is the area below 3 cos x + 3?? and how do i find it?!?

Answer 1

I think what you do is integrate over the x and y for the area
2π..3 cos x + 3
∫......∫ dy dx
0....0

2π
∫ 3 cos x + 3 dx
0

3 sin x + 3x evaluate between 2π and 0

= 3(2π) = 6π
under 0 and 2π

Answer 2

Taking the intervall o_2pi
A= 3 Int( cos x+1) dx (o,2pi)= 3 (sinx+x) ( 0,2pi)= 6*pi