Math help??? Poloynomails???

Question

Factor the following polynomial completely.
22x5 - 154x2


Factor the following polynomial completely.
1 x^2 - 4 x + 4


Factor the following polynomial completely.
121 x**2 - 25


I've tried them numerous times and I have no idea what I'm doing wrong.... any help would be greatly appreciated....

Answer 1

22x5 - 154x2
= 22x^2(x^3 -7)

1 x^2 - 4 x + 4
= (x-2)^2

121 x^2 - 25
= (11x-5)(11x+5)

Answer 2

Try factoring them down to prime numbers and x's:
22x⁵ - 154x² = (2∙11∙x∙x∙x∙x∙x) - (2∙7∙11∙x∙x)

The two terms are both have 2∙11∙x∙x, so factor that out:
= (2∙11∙x∙x)(x∙x∙x - 7)
= 22x²(x³-7)

Answer 3

1)

22x^5 - 154 x^2

22x^2(x^3 - 7)

2)

x^2 - 4x + 4

=>(x-2)^2

3)

121 x^2 - 25

(11x)^2 - (5)^2

=>(11x +5)(11x-5)

Answer 4

1. 22x^2(x^3-7) - you can factor further, but you'll have to use irrational numbers. (a^3-b^3) = (a-b)(a^2+ab+b^2)

2. (x-2)^2

3. (11x-5)(11x+5)

Answer 5

22x^5-154x^2
=22x^2(x^3-7)




x^2-4x+4
=x^2-2x-2x+4
=x(x-2)-2(x-2)
=(x-2)(x-2)







121x^2-25
=(11x)^2-5^2
=(11x+5)(11x-5)