Calculate the solubility in grams per liter of Hg2Cl2,
Ksp = 1.10 x 10-18 ,
any help would be greatly appreciaTEd!
2007-11-01 12:10:13 · 2 answers · asked by nietzsche 1 in Science & Mathematics ➔ Chemistry
You do not need to know how much Hg2Cl2 you have in the water for solubility calculation. Further, solid should never appear in the presentation of Ksp. But, which one solid are you talking about, HgCl2 or Hg2Cl2?
Let me assume it is Hg2Cl2. Let X be [Hg2Cl2], the solubility of Hg2Cl2. Hence the concentration [Hg+] = 2X, and [Cl-] = 2X.
Ksp = 1.10x10-18 = (2X)^2(2X)^2 = 16X^4
Now you do the math to solve X.
2007-11-03 19:02:56 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋
First you need to know how much Hg2Cl2 you have in the water than knowing that ksp=(products)/reactants you can set up an equation like this ksp=x^2/(moles of Hg2Cl2) then solve for x this is the moles of the products that are in the solution
2007-11-01 19:29:45 · answer #2 · answered by David J 3 · 0⤊ 0⤋