I have struggled with this problem. I need to know the formula to use and how to solve this problem. Thnks?

Question

A cue stick hit a cue an average force of 23N for a duration of 0.028 s.If the mass of the ball is 0.16 kg, how fast is it moving after being struck?

Answer 1

F = m * v / t
23 = 0.16 / 0.028 * v
v = 4.025 m/s

Answer 2

Force * Time = Mass * Velocity
Velocity = Force * Time / Mass
= 23 * 0.028/0.16 = 4.025 m/s

Answer 3

Hi,
In a word: 4.025 m/s
This is an impulse problem expressed by the equation:
Ft = mv2-mv1
In your problem v1 = 0, so you have this:
Ft = mv2
23 kg*m/s²(0.028)s = 0.16kg*vm/s
(0.644 kg*m/s)/0.16kg = v m/s
4.025 m/s = v

FE