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The density of seawater is 1025 kg/m3.

a) If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius = 0.11 m)?

b) For comparison, determine the weight of a jetliner whose mass is 1.5 x 10^5 kg.

2007-11-01 10:49:13 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

First, get the pressure.

Pr= Density*Depth*g

To get the force multiply pressure times Area.

F= Pr * pi* (r)^2

I'll let you do the math. Although it will be somewhere between 4.4 x 10^6 and 4.6 x 10^6 Newtons which is more than the weight of the jetliner!

Good luck.

2007-11-05 05:39:00 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 0 0

a) about 1325 tonnes.

2007-11-01 10:53:37 · answer #2 · answered by Alexander 6 · 0 1

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