2007-11-01 10:29:21 · 8 answers · asked by brunettebelle10 2 in Science & Mathematics ➔ Mathematics
(3x+5)(x-7) is the factors.
2007-11-01 12:05:30 · answer #1 · answered by I Need Help 4 · 0⤊ 0⤋
Do it in stages:
To get the lead term, you MUST have
( 3x +/- something) ( x +/- something)
To be more succinct
( 3x + a)(x + b)
Why have I now changed to both + signs?
Because one of a or b might be -ve, but we'll find out as we go!
Those two numbers MUST be 5, 7 or 7,5.
O.K. so try some possibilities.
Could it be (3x + 5)(x + 7) NO we are getting +35, not -35.
Could it be (3x + 7)(x + 5) NO again.
Could it be (3x - 5)(x + 7) No, it will not give the right x term.
Could it be (3x + 5)(x - 7) YES, that is correct.
2007-11-01 10:45:09 · answer #2 · answered by anthony@three-rs.com 3 · 0⤊ 0⤋
3 x ² - 16 x - 35 = ( 3 x + 5 ) ( x - 7 )
2007-11-01 12:42:25 · answer #3 · answered by Como 7 · 0⤊ 0⤋
Use the version-of-squares formulation: a^2 - b^2 = (a + b)(a - b) replace 4x^2 (sq. root of 16x^4) for a and 9 (sq. root of 80 one) for b: 16x^4 - 80 one = (4x^2 + 9)(4x^2 - 9) prepare an same rule to the (4x^2 - 9): 4x^2 - 9 = (2x + 3)(2x - 3) That makes the comprehensive factoring: (4x^2 + 9)(2x + 3)(2x - 3)
2017-01-04 17:16:38 · answer #4 · answered by contes 3 · 0⤊ 0⤋
3x^2 - 16x - 35 =
(3x + 5)(x - 7)
2007-11-01 10:34:02 · answer #5 · answered by lenpol7 7 · 0⤊ 0⤋
3x^2-16x-35
(3x+5)(1x-7)
2007-11-01 10:36:41 · answer #6 · answered by george p 2 · 0⤊ 0⤋
(3x +5)(x-7) and you should do your own school
2007-11-01 10:34:52 · answer #7 · answered by Anonymous · 0⤊ 0⤋
(3x +5)(x-7)
2007-11-01 10:32:11 · answer #8 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋