2007-11-01 09:49:35 · 4 answers · asked by Fung 1 in Science & Mathematics ➔ Chemistry
Sorry, I know you probably want a logic answer...but I can't resist!
Say wha'?
2007-11-01 09:52:49 · answer #1 · answered by diabolicus2007 2 · 0⤊ 0⤋
You need to compute the number of moles of each. Since the pressure per mole of the gases will be equal, you will have p(H2)/m(H2) = p(Xe)/m(Xe), and p(H2) + p(Xe) = 0.435. Routine algebra gives the solution.
2007-11-01 09:57:18 · answer #2 · answered by Anonymous · 0⤊ 0⤋
moles(H2) = 6.40/2 = 3.2 moles(H2)
moles(Xe) = 10.8/131 = 0.082
Ratios H2 ; Xe :: 3.2 ; 0.082
Ratios H2 ;Xe ;; 3.2/0.082 ; 0.082/0.082
Ratios H2 : Xe :: 39 : 1
Therefore partial press sure of H2 = 0.435 x 39/(39 +1) = 0.424 atm.
2007-11-01 09:59:37 · answer #3 · answered by lenpol7 7 · 0⤊ 0⤋
what is that, stoichiometry???im learning the same thing in class right now and not doing too good.
2007-11-01 09:53:23 · answer #4 · answered by Anonymous · 0⤊ 0⤋