Can't be factored. No real zeroes!
ax^2 + bx + c
If you try:
b^2 - 4ac and it is less than zero, then it cannot be factored.
Hope that helps!
2007-11-01 08:13:44
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answer #1
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answered by Hubris 2
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4x^2-2x+1.
Factors of 4 are: 2,2; 4,1.
Factors of 1: 1. TRY:
+1 means same signs, either both plus, or both minus.
(2x +1)(2x +1 ), no
(2x -1)(2x -1 ), no
(4x -1)(x -1 ), no
(4x +1)(x +1 ), no
Not factorable.
2007-11-01 15:14:10
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answer #2
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answered by pbb1001 5
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if you look at the first term ,ii is square of 2x , the last square of 1
so (2x+1)^2= 4x2+4x+1
and 4x^2-2x+1 = (2x+1)^2-6x 6x is the square of (6x)^0.5
so 4x2+4x+1 = (2x+1-(6x)^05)*(2x+1+(6x)^05)
2007-11-01 15:18:34
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answer #3
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answered by maussy 7
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4x^2-2x+1=0
x=[2+/-sqrt(4-16)]/8
=1/4+/-i sqrt(3)/4
the desired factors are:
[x-1/4-isqrt(3)/4][x-1/4+i sqrt(3)/4].ANS.
2007-11-01 15:40:26
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answer #4
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answered by Anonymous
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