English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2007-11-01 08:07:19 · 4 answers · asked by RogerDodger 1 in Science & Mathematics Mathematics

4 answers

Can't be factored. No real zeroes!

ax^2 + bx + c

If you try:

b^2 - 4ac and it is less than zero, then it cannot be factored.

Hope that helps!

2007-11-01 08:13:44 · answer #1 · answered by Hubris 2 · 0 0

4x^2-2x+1.

Factors of 4 are: 2,2; 4,1.

Factors of 1: 1. TRY:

+1 means same signs, either both plus, or both minus.

(2x +1)(2x +1 ), no
(2x -1)(2x -1 ), no
(4x -1)(x -1 ), no
(4x +1)(x +1 ), no

Not factorable.

2007-11-01 15:14:10 · answer #2 · answered by pbb1001 5 · 0 0

if you look at the first term ,ii is square of 2x , the last square of 1
so (2x+1)^2= 4x2+4x+1
and 4x^2-2x+1 = (2x+1)^2-6x 6x is the square of (6x)^0.5

so 4x2+4x+1 = (2x+1-(6x)^05)*(2x+1+(6x)^05)

2007-11-01 15:18:34 · answer #3 · answered by maussy 7 · 0 0

4x^2-2x+1=0
x=[2+/-sqrt(4-16)]/8
=1/4+/-i sqrt(3)/4
the desired factors are:
[x-1/4-isqrt(3)/4][x-1/4+i sqrt(3)/4].ANS.

2007-11-01 15:40:26 · answer #4 · answered by Anonymous · 0 0

fedest.com, questions and answers