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need details as to how you get the answer to this question.

2007-11-01 07:35:52 · 6 answers · asked by Dixie 1 in Science & Mathematics Mathematics

6 answers

Its looks like 3/2 is an exponent. So, its really:

x^3/2= 27

In this case, the radical form would be the square root of

x^3
where the index is 2.

First step is to remove the radical. To do this, square both sides:

1. x^3 = 729

Transpose 729 to other side,

x^3 - 729 = 0

Factoring

2. (x - 9)(x² + 9x + 81) = 0

Theorem: If ab=0 then either a=0 or b=0

So either x - 9 = 0 or x² + 9x + 81 = 0 (2nd expression has imaginary roots)

x = 9

2007-11-01 07:54:03 · answer #1 · answered by Tech808 3 · 0 0

is the 3/2 supposed to be an exponent? Exponents are written using the caret ^ symbol

x^(3/2) = 27

(x^(3/2))^2/3 = 27^(2/3)
x = 9

2007-11-01 07:54:21 · answer #2 · answered by Demiurge42 7 · 0 0

Do you mean 3/2x=27? If that's the equation, then you should divide both sides by 3/2. The answer should be 18.

2007-11-01 07:40:35 · answer #3 · answered by Anonymous · 0 1

3/2*x=27

Multiply each side by 2/3

then the 3/2 cancels out on the left hand side

you are left with 27*2/3

so x=18

2007-11-01 07:40:22 · answer #4 · answered by cody s 2 · 0 1

Solving for x?

x (3/2) = 27
3x/2 = 27
2* (3x/2 )= 2* (27)
3x = 54
(3x)/3 = (54)/3
x = 18

2007-11-01 07:39:28 · answer #5 · answered by poniegirle 2 · 0 1

multiply both sides by 2

3x = 56

divide both sides by 3

x = 18.667

2007-11-01 07:39:04 · answer #6 · answered by cmcg83 2 · 0 1

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