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To beat a computer at chess?

2007-11-01 06:00:08 · 12 answers · asked by Leslie Chow 3 in Games & Recreation Board Games

and don't say 4...

2007-11-01 06:00:34 · update #1

i mean grand master lever computer program

2007-11-01 06:01:01 · update #2

The program on my computer is just called Chess. I can beat it in 12 moves right now.

2007-11-01 07:26:56 · update #3

12 answers

actually believe it or not is 6

2007-11-01 06:03:14 · answer #1 · answered by crystal t 2 · 1 0

It actually depends on how good you are and if you are purposely trying to do a quick checkmate. However, there is a 5 move, sorry, I don't know it, but maybe the grandmaster program will fall 4 it...doubt it though.

2007-11-01 21:42:44 · answer #2 · answered by chessmedalist 1 · 0 0

The average game takes 20-60 moves. Sorry for the wide range, maybe 25-55 is better.:) Computer, strong human, same thing.

2007-11-03 13:09:34 · answer #3 · answered by Anonymous · 0 0

which program are you using. 3 i know of.

all three when first set up can be beaten in 5-7 moves. depending on you counter move.

remember the computer learns your moves as you play against it and documents your pattern.

2007-11-01 13:11:46 · answer #4 · answered by ahsoasho2u2 7 · 1 0

Well when i play stupid people @ chess hahahaha I can beat them with 3 moves.

2007-11-01 13:04:54 · answer #5 · answered by jurbanator13 2 · 0 1

assuming you mean "level" not "lever"
assuming you are good enough to beat it, because of the way it works, probably 30-40 moves.

2007-11-01 13:03:51 · answer #6 · answered by Mike1942f 7 · 0 1

Your question should be "Can you beat a grandmaster lever (lol) computer?"

2007-11-01 16:11:42 · answer #7 · answered by budthestud 2 · 0 0

Tis 6.

2007-11-01 13:17:46 · answer #8 · answered by Anonymous · 1 0

it varies with your game plan...it can take as many as 25 to 100 depending on how well you play and what your opening is.

2007-11-01 13:14:57 · answer #9 · answered by dsizz516 3 · 0 1

i think its around 20

2007-11-01 17:22:27 · answer #10 · answered by Ben R 2 · 0 0

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