2007-11-01 05:16:00 · 10 answers · asked by amylc06 1 in Science & Mathematics ➔ Mathematics
For any event A, the probability of not A is 1 - P(A). This is one of the axioms of probability.
since a fair die has 1/6 probability of landing on 3, then the probability of not 3 is 1 - 1/6 = 5/6
axioms of probability
1. Let S be a sample space, P(S) = 1
2. For any event A, 0 ≤ P(A) ≤ 1
3. If A and B are mutually exclusive events then P(A U B) = P(A) + P(B)
More generally, if A1, A2, A3, ... are mutually exclusive, then P(A1 U A2 U A3 U ...) = P(A1) + P(A2) + P(A3) + ...
2007-11-03 16:46:56 · answer #1 · answered by Merlyn 7 · 0⤊ 0⤋
P (not a 3) = 5 / 6
2007-11-01 05:23:13 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Single Fair Die
2017-01-09 11:55:13 · answer #3 · answered by ? 4 · 0⤊ 0⤋
5/6
2007-11-01 05:19:12 · answer #4 · answered by Anonymous · 0⤊ 0⤋
p(3) = 1/6, so p(~3) = 1 - 1/6 = 5/6
2007-11-01 05:20:35 · answer #5 · answered by John V 6 · 1⤊ 0⤋
5 chances out of 6
2007-11-01 05:21:43 · answer #6 · answered by mom 7 · 0⤊ 0⤋
There are 6 numbers on the die, and 5 non-3, so the chances of a non-3 are 5 in 6 or 5/6
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2007-11-01 06:17:47 · answer #7 · answered by krazykyngekorny 4 · 0⤊ 0⤋
1/6 * 1/6 = 1/36 using proporitons, I turned 1/36 into a percentage and got 2.7(repeating)
2016-05-26 21:51:34 · answer #8 · answered by ? 3 · 0⤊ 0⤋
number of favourible outcomes divided by the number of possible outcomes.
=> 5/6 (numbers 1,2,4,5,6 divided by all numbers 1-6)
2007-11-01 05:26:52 · answer #9 · answered by MrBuzz 4 · 0⤊ 0⤋
5/6 BEH.BIE
2007-11-01 05:31:38 · answer #10 · answered by Anonymous · 0⤊ 0⤋