2007-11-01 05:10:28 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
24½ + 7/32
24 + 16/32 + 7/32
24 + 23/32
24 23/32
2007-11-01 05:32:33 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Both numbers in the problem need to be expressed as fractions, so it turns out to be
791/16 divided by 2/1
(The 791 we get by multiplying the denominator 16 by the whole number 49 and adding the numerator 7 -- 16 X 49 + 7.)
Since this is a division problem, we have to invert (flip) the second expression and multiply that so the problem now reads
791/16 X 1/2
multiply 791 X 1 = 791
multiply 16 X 2 = 32
So your final answer is 791/32, and it is irreducible because 791 is a prime number, a number divisible by only 1 and itself. A good way to determine if three digit numbers are prime or factorable is to add the individual digits; if they form a prime number, then the number itself is. 7+9+1 = 17, which IS a prime number.
2007-11-01 05:24:40 · answer #2 · answered by ensign183 5 · 0⤊ 0⤋
convert 49 7/16 into a fraction with no whole numbers:
(49*16+7)/16 = 791/16
Then multiply by 1/2:
(791/16) * (1/2) = 791/32
Cannot simplify 791/32 so this is your final answer.
Converting it back to whole numbers and fractions:
791/32 = 24.7...
791 - (24*32) = 23
Therefore it is: 24 23/32
2007-11-01 05:15:43 · answer #3 · answered by rAOL 1 · 0⤊ 0⤋
Someone forgot the 49 :).
24 23/32
2007-11-01 05:15:36 · answer #4 · answered by greenshootuk 6 · 0⤊ 0⤋
497/16 devided by 2 = 497/ 32
= 15.93 125
2007-11-01 05:21:27 · answer #5 · answered by Pramod Kumar 7 · 0⤊ 0⤋
49 7/32
1/16 * 1/2 = 1/32
J
2007-11-01 05:13:41 · answer #6 · answered by Jay D 2 · 0⤊ 1⤋