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8 answers

Each processor has a certain word length that is can process. These work lengths are determined by three things.
1. The operating system - Does the OS allow for 32 bit or 64 bit?
2. The bus size and architecture - Does bus use a 32 bit or 64 bit architecture
3. The processor - Is it a 32 bit or 64 bit processor

The smallest one will limit the word size of your system.
A 64 bit word system can store more data in one register than a 32 bit system, twice as much to be exact.

2007-11-01 05:12:45 · answer #1 · answered by Craig V 3 · 0 0

the main info u need to know is that if u run a 64bit operating system u need a 64 bit processor, 64 bit operating system, 64 bit drivers, and 64 bit software for it to work in 64 bit ... 32 bit is the same ... needs to be all 32 bit but 32 bit will run on 64 bit hardware ..

2007-11-01 05:11:35 · answer #2 · answered by Anonymous · 0 1

It is a term about processors and compatible operating system.
Nowadays people use two types of processors, 32 bit and 64 bit. For these processors, compatible operating systems are available. e.g. Windows vista ultimate 64 bit

2007-11-01 12:05:41 · answer #3 · answered by shailesh.giri 2 · 0 0

A bit is a single piece of digitial information (either a "1" or a "0").

The use of 32 bit or 64 bit in reference to chips and OS's refers to the complexity of the coding in the OS - generally for purposes of Security.

2007-11-01 05:15:31 · answer #4 · answered by jcurrieii 7 · 0 0

It refers to a computer's architecture. One significant difference between the two is the way they address memory. The theoretical limit for a 32 bit machine is 4 GB and the theoretical limit for a 64-bit architecture is 16 TB.

The following link is in terms of XP but you can get the point.

ttp://www.softwaretipsandtricks.com/windowsxp/articles/581/1/The-difference-between-64-and-32-bit-processors

2007-11-01 05:11:05 · answer #5 · answered by brie aleida 1 · 0 1

"64-bit" computer architecture generally has integer registers that are 64 bits wide, which allows it to support (both internally and externally) 64-bit "chunks" of integer data.
"32-bit" would be 32 bits wide.

2007-11-01 05:14:50 · answer #6 · answered by -=Seta San=- 6 · 0 0

Just look at the answers above me as they r right

2007-11-01 05:20:56 · answer #7 · answered by A Human 3 · 0 1

only if you can help me with my algebra....

2007-11-01 05:09:29 · answer #8 · answered by Anonymous · 0 1

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