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CH3CH2CH2CH2-OH2+ + Br- →
CH3CH2CH2CH2-Br + H2O
using a strong acid to protonate the —OH group in the presence of the bromide ion, which changes the leaving group from hydroxide to water, and allows the bromide to react with it in the same mixture.
sulfuric acid is a dehydrating agent. butanol when mixed with sodium bromide and added with sulfuric acid will produce 1-bromobutane.

2007-11-01 05:16:13 · answer #1 · answered by purple_iris2004 3 · 0 0

CH3CH2CH=CH2 1-Butene
(CH3CH2CH2CH2)2O Di-n-butyl ether

2007-11-01 12:01:19 · answer #2 · answered by steve_geo1 7 · 0 0

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