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we have a circle with the center ( x-center , y-center ) and the radius ( r-circle ).
so how can we find the end points on this circle ( x-end , y-end ).
for example x-center = 20 , y-center = 20 , r-circle = 10 , what is the x-end and y-end. ( ( x-center , y-center ) is the central point and ( x-end , y-end ) is on of the points on circumference )

2007-11-01 02:23:38 · 3 answers · asked by Sepehr 2 in Science & Mathematics Mathematics

3 answers

Circular graph in basic form is y^2 = r^2 - x^2 where the center is at ( 0 , 0 ) and r is the radius.

Your graph goes like this (y - 20)^2 = 10^2 - (x - 20)^2

every n thick, (n is from 0 - 59)
endX = centerX+(radius*(cos(90-6n)) (90 in degrees)
endY = centerY+(radius*(sin(90-6n)) (90 in degrees)

:)

2007-11-01 02:35:07 · answer #1 · answered by pinhead 4 · 0 0

The general equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2
h is what you called x-center
k is what you called y-center

To find the points on the circle, just plug in a value for x and you will come up with the 2 values of y, corresponding to the 2 points on the circle having the same x coordinate.

Remember though, that you can only use values of x such that h-r <= x <= h+r

2007-11-01 09:47:35 · answer #2 · answered by BB 2 · 0 0

A point is unique, only one.
But a line (whether straight or circular), consists of infinite number of points.
I think we can find these points by setting limits.

2007-11-01 09:35:13 · answer #3 · answered by rene c 4 · 0 0

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