2(a-8)+7 = 5(a+2)-3a-19 Write original problem
2a-16+7 = 5a+10-3a-19 Use distribuitve property to multiply
the term in front of the parenthese
to the terms inside the parenthes.
2a-9=2a-9 Combine like terms
+9 +9 Add 9 on both sides
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2a=2a + 0 Subtract 2a on both sides.
-2a -2a
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0=0 Infinite amount of solutions
2007-11-01 01:51:25
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answer #1
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answered by Anonymous
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2(a-8)+7=5(a+2)-3a-19
2a-16+7 = 5a+10-3a-19
2a-5a+3a = 10-19+16-7
0 = 0
there seems to some mistake in writing down the equation
2007-10-31 18:05:29
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answer #2
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answered by Anonymous
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2(a-8)+7=5(a+2)-3a-19
2a-16+7=5a+10-3a-19
2a - 9 = 2a - 9
The expression on the left and the right are the same equation (or same line). So, if you plot these two together on the same xy-plane, these two lines are directlly on top of each other. Hence, there are infinitely many solutions.
2007-10-31 18:07:58
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answer #3
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answered by -eR!c- 2
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2a - 16 + 7 = 5a + 10 - 3a - 19
2a - 9 = 2a - 9
Leading nowhere unfortunately.
2007-11-01 00:38:55
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answer #4
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answered by Como 7
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The Left Hand SIde and The Right Hand side are the same.
For all values of a, that equation is as always fulfilled.
2007-10-31 18:08:46
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answer #5
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answered by wangsacl 4
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its infinitive number of solutions cuz after i do everything, it become 2a-9=2a-9
2007-10-31 18:05:51
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answer #6
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answered by khiem 1
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a can take any value and the equation will be valid
2007-10-31 18:11:10
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answer #7
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answered by Hazem 1
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they are equal on LHS and RHS
2007-10-31 18:05:34
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answer #8
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answered by devil 1
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