Once again... I have answers just need help figuring out how to work them out. This is almost a daily occurance for me.. so if you like physics questions I'm your girl!
. A bowling ball (m = 7.2 kg, r = 0.11 m) and a billiard ball (m = 0.38 kg, r = 0.028 m) may each be treated as uniform spheres. What is the magnitude of the maximum gravitational force that each can exert on the other?
2007-10-31 17:14:06 · 1 answers · asked by PinkyTrauma 2 in Science & Mathematics ➔ Physics
PinkyTrauma:
This requires Newton's law of Universal Gravity:
F=G*m1*m2/r^2
Uniform spheres, for purposes of gravity, can be treated as if all of the mass is located at their center.
Therefore the closests the two centers can be to each other is the sum of the two radius.
R=Rbowling+ Rbilliard
=.138 m
F=G*7.2kg*.38kg/(.138)^2
where
G=6.67 × 10^−11 N m^2 kg^−2
Plug G in and go.
Remo.
2007-10-31 18:02:11 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 0⤊ 0⤋