a 873kg dragster, starting from rest, attains a speed of 26.3 m/s in .59s
A.) find the avergae acceleration of the dragster during this time interval
B.) what is the magnitude of the average net force on the dragster during this time?
C.) assume that the driver has a mass of 68 kg. what horizontal force does the seat exert on the driver?
2007-10-31 14:13:16 · 2 answers · asked by kiwi 1 in Science & Mathematics ➔ Physics
A)
Acceleration = [v - u] /t
a =
[26.3 - 0] / 0.59 = 44.58 m/s^2
B)
Force = mass x acceleration
F = 873 x44.58 = 38918.34 N
C)
Force = mass x acceleration
F = 68 x [- 44.58= - 3046.4 N
Negative sign denotes force is opposite to the direction of motion
2007-10-31 15:46:29 · answer #1 · answered by Pearlsawme 7 · 0⤊ 0⤋
Do you own a Dragster or are you trying to get someone to do your physics homework ?
2007-10-31 21:16:50 · answer #2 · answered by Will 4 · 0⤊ 0⤋