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Fairgoers ride a Ferris wheel with a radius of 6.00 m (Figure 4-18), the bottom of which is 1.75 m above the ground. The wheel completes one revolution every 28.0 s.

Figure 4-18


(b) If a rider accidentally drops a stuffed animal at the top of the wheel, where does it land relative to the base of the ride? (Neglect air resistance.)
m

2007-10-31 13:45:40 · 2 answers · asked by Chris B 1 in Science & Mathematics Physics

Fairgoers ride a Ferris wheel with a radius of 6.00 m (Figure 4-18), the bottom of which is 1.75 m above the ground. The wheel completes one revolution every 28.0 s.

Figure 4-18


(b) If a rider accidentally drops a stuffed animal at the top of the wheel, where does it land relative to the base of the ride? (Neglect air resistance.)
m

any help would great thanks

2007-10-31 13:59:09 · update #1

2 answers

h = 2r+1.75
hor. velocity v = ωr = 2pi*r/28
fall time t = sqrt(2h/g)
hor. distance = vt

2007-11-03 06:31:04 · answer #1 · answered by kirchwey 7 · 0 0

help on this

2015-01-30 14:17:40 · answer #2 · answered by sarah k 1 · 0 0

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