She serves aball from a height of .84m and has an initial velocity of +8.3 m/s straight up.How high will it go

Answer 1

Since u (initial velocity), v (final velocity =0), and a (acceleration due to gravity = - 9.81 m/s) are known, substitute in the equation v^2 = u^2 + 2 a s ( to find the distance, s). THEN add 0.84 m to find the height.